If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4.905t^2+330t-1320=0
a = 4.905; b = 330; c = -1320;
Δ = b2-4ac
Δ = 3302-4·4.905·(-1320)
Δ = 134798.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(330)-\sqrt{134798.4}}{2*4.905}=\frac{-330-\sqrt{134798.4}}{9.81} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(330)+\sqrt{134798.4}}{2*4.905}=\frac{-330+\sqrt{134798.4}}{9.81} $
| Y=P13,687.50+P5.25x | | Y=P19,780+P4.28x | | −3(x+3)+14=12−4x | | Y=P17,333.33=P4.67x | | -10=n-58/5 | | 2(x+9)-2=46-3x | | 2(x+9)−2=46−3x | | X2-6x-32=0 | | 2k/5+8=10 | | 2(3y-1)+3=21 | | 4/5(x)+4=12 | | -7x²=-448 | | 10x+6x-32=0 | | -7x²=448 | | x=10x^2 | | (x+(x*0.1))+(((x+(x*0.1))*1.19)=1600 | | 7+x÷5=18 | | X(x-8)=25 | | -5(2+y)=15 | | 2u^2=10u | | 2u^2=10 | | 1/4(m)=3+7 | | 5a/9=12 | | -6x-8x-6=-164 | | (x+(x*0.1))*1.19=1600 | | 0.42857142857x-5=4 | | P-3q2+10q=5 | | 7+5(p-1)=42 | | 0.1x+0.3x/0.5+2/0.5=0.5 | | 7/9c=42 | | 3x-6=×/3+6 | | h+15=89 |